-2x^2+32x=-34

Solution for -2x^2+32x=-34 equation:

-2x^2+32x=-34

We move all terms to the left:

-2x^2+32x-(-34)=0

We add all the numbers together, and all the variables

-2x^2+32x+34=0

a = -2; b = 32; c = +34;
Δ = b2-4ac
Δ = 322-4·(-2)·34
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-36}{2*-2}=\frac{-68}{-4}
=+17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+36}{2*-2}=\frac{4}{-4}
=-1
$